The dominant hand is 10% stronger than the non-dominant hand. The dominant hand is what percent stronger than the non-dominant hand?

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Multiple Choice

The dominant hand is 10% stronger than the non-dominant hand. The dominant hand is what percent stronger than the non-dominant hand?

Explanation:
The key idea is that “percent stronger” is measured relative to the weaker hand. If the non-dominant hand is treated as the baseline, a 10% increase means the dominant hand is 10% more powerful than the non-dominant. Imagine the non-dominant hand has 100 units of strength. If the dominant hand is 10% stronger, it would be 110 units. The extra 10 units represent 10% of the non-dominant hand, so the dominant hand is 10% stronger than the non-dominant. So the correct percent stronger is 10%. This wouldn’t be 5% or another value because those would arise from using a different baseline (like the average of both hands), which isn’t how “percent stronger than” is usually interpreted.

The key idea is that “percent stronger” is measured relative to the weaker hand. If the non-dominant hand is treated as the baseline, a 10% increase means the dominant hand is 10% more powerful than the non-dominant.

Imagine the non-dominant hand has 100 units of strength. If the dominant hand is 10% stronger, it would be 110 units. The extra 10 units represent 10% of the non-dominant hand, so the dominant hand is 10% stronger than the non-dominant.

So the correct percent stronger is 10%. This wouldn’t be 5% or another value because those would arise from using a different baseline (like the average of both hands), which isn’t how “percent stronger than” is usually interpreted.

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